(2x+3)^2/3=8

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Solution for (2x+3)^2/3=8 equation: 


x in (-oo:+oo)

((2*x+3)^2)/3 = 8 // - 8

((2*x+3)^2)/3-8 = 0

((2*x+3)^2)/3+(-8*3)/3 = 0

(2*x+3)^2-8*3 = 0

4*x^2+12*x-15 = 0

4*x^2+12*x-15 = 0

4*x^2+12*x-15 = 0

DELTA = 12^2-(-15*4*4)

DELTA = 384

DELTA > 0

x = (384^(1/2)-12)/(2*4) or x = (-384^(1/2)-12)/(2*4)

x = (8*6^(1/2)-12)/8 or x = (-8*6^(1/2)-12)/8

(x-((-8*6^(1/2)-12)/8))*(x-((8*6^(1/2)-12)/8)) = 0

((x-((-8*6^(1/2)-12)/8))*(x-((8*6^(1/2)-12)/8)))/3 = 0

((x-((-8*6^(1/2)-12)/8))*(x-((8*6^(1/2)-12)/8)))/3 = 0 // * 3

(x-((-8*6^(1/2)-12)/8))*(x-((8*6^(1/2)-12)/8)) = 0

( x-((-8*6^(1/2)-12)/8) )

x-((-8*6^(1/2)-12)/8) = 0 // + (-8*6^(1/2)-12)/8

x = (-8*6^(1/2)-12)/8

( x-((8*6^(1/2)-12)/8) )

x-((8*6^(1/2)-12)/8) = 0 // + (8*6^(1/2)-12)/8

x = (8*6^(1/2)-12)/8

x in { (-8*6^(1/2)-12)/8, (8*6^(1/2)-12)/8 }

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